tag:blogger.com,1999:blog-123604111616439794.post907422731075448447..comments2020-10-05T09:21:10.019-07:00Comments on Statistics for Business and Economics: Confidence IntervalChuck Stullhttp://www.blogger.com/profile/16764698108162760118noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-123604111616439794.post-16535813786521005102011-05-08T11:01:16.191-07:002011-05-08T11:01:16.191-07:00Standard Error = s/√n = 56/√13 = 15.53
Degrees of ...Standard Error = s/√n = 56/√13 = 15.53<br />Degrees of Freedom = n-1 = 13-1 = 12<br />t-table value = 2.179<br /><br />x̄ ± t(s.e.)<br /><br />220 + (2.179)(15.53) = 220 + 33.83987 = 253.83987<br />220 – (2.179)(15.53) = 220 – 33.83987 = 186.16013<br /><br />ANSWER<br />Interval: 186.16-253.84Jasmine Okamotohttps://www.blogger.com/profile/11895954838732462115noreply@blogger.com